Examples with MapType io.confluent.ksql.function.types.MapType used on opensource projects

Example 6 with MapType

use of io.confluent.ksql.function.types.MapType in project ksql by confluentinc.

the class GenericsUtil method resolveGenerics.

/**
 * Identifies a mapping from generic type to concrete type based on a {@code schema} and
 * an {@code instance}, where the {@code instance} schema is expected to have no generic
 * types and have the same nested structure as {@code schema}. Any Generic type mapping
 * identified is added to the list passed in.
 *
 * @param mapping   a list of GenericType to SqlType mappings
 * @param schema    the schema that may contain generics
 * @param instance  a schema with the same structure as {@code schema} but with no generics
 *
 * @return whether we were able to resolve generics in the instance and schema
 */
// CHECKSTYLE_RULES.OFF: NPathComplexity
// CHECKSTYLE_RULES.OFF: CyclomaticComplexity
private static boolean resolveGenerics(final List<Entry<GenericType, SqlType>> mapping, final ParamType schema, final SqlArgument instance) {
    if (!isGeneric(schema) && !matches(schema, instance)) {
        // cannot identify from type mismatch
        return false;
    } else if (!hasGenerics(schema)) {
        // nothing left to identify
        return true;
    }
    KsqlPreconditions.checkArgument(isGeneric(schema) || (matches(schema, instance)), "Cannot resolve generics if the schema and instance have differing types: " + schema + " vs. " + instance);
    if (schema instanceof LambdaType) {
        final LambdaType lambdaType = (LambdaType) schema;
        final SqlLambda sqlLambda = instance.getSqlLambdaOrThrow();
        if (lambdaType.inputTypes().size() == sqlLambda.getNumInputs()) {
            if (sqlLambda instanceof SqlLambdaResolved) {
                final SqlLambdaResolved sqlLambdaResolved = (SqlLambdaResolved) sqlLambda;
                int i = 0;
                for (final ParamType paramType : lambdaType.inputTypes()) {
                    if (!resolveGenerics(mapping, paramType, SqlArgument.of(sqlLambdaResolved.getInputType().get(i)))) {
                        return false;
                    }
                    i++;
                }
                return resolveGenerics(mapping, lambdaType.returnType(), SqlArgument.of(sqlLambdaResolved.getReturnType()));
            } else {
                return true;
            }
        } else {
            return false;
        }
    }
    final SqlType sqlType = instance.getSqlTypeOrThrow();
    if (isGeneric(schema)) {
        mapping.add(new HashMap.SimpleEntry<>((GenericType) schema, sqlType));
    }
    if (schema instanceof ArrayType) {
        final SqlArray sqlArray = (SqlArray) sqlType;
        return resolveGenerics(mapping, ((ArrayType) schema).element(), SqlArgument.of(sqlArray.getItemType()));
    }
    if (schema instanceof MapType) {
        final SqlMap sqlMap = (SqlMap) sqlType;
        final MapType mapType = (MapType) schema;
        return resolveGenerics(mapping, mapType.key(), SqlArgument.of(sqlMap.getKeyType())) && resolveGenerics(mapping, mapType.value(), SqlArgument.of(sqlMap.getValueType()));
    }
    if (schema instanceof StructType) {
        throw new KsqlException("Generic STRUCT is not yet supported");
    }
    return true;
}

Example 7 with MapType

use of io.confluent.ksql.function.types.MapType in project ksql by confluentinc.

the class GenericsUtilTest method shouldFailIdentifyMismatchStructureGeneric.

@Test(expected = KsqlException.class)
public void shouldFailIdentifyMismatchStructureGeneric() {
    // Given:
    final MapType a = MapType.of(GenericType.of("A"), GenericType.of("B"));
    final SqlArgument instance = SqlArgument.of(SqlTypes.array(SqlTypes.STRING));
    // When:
    GenericsUtil.reserveGenerics(a, instance);
}